[R-SIG-Finance] column transposition with xts
Joshua Ulrich
josh.m.ulrich at gmail.com
Tue Sep 15 04:52:19 CEST 2009
Aleks,
This isn't the most elegant solution, especially with large data sets,
but it is *a* solution. The code below yields a 24-column xts object
(20 lags of close prices, plus the original OHLC series).
library(xts)
library(quantmod)
data(sample_matrix)
x <- as.xts(sample_matrix[1:50,])
res <- x
for(i in 1:20) { res <- cbind(res,lag(Cl(x),i)) }
HTH,
Josh
--
http://www.fosstrading.com
On Mon, Sep 14, 2009 at 5:53 AM, Aleks Clark <aleks.clark at gmail.com> wrote:
> I'm working with SVMs and have recently migrated to using TTR and thus xts,
> but I've run into the following problem:
>
> For each vector in an SVMs training set, I need to have a given amount of
> historical data available as features for the vector. A simple example would
> be to have the past 20 close prices. So I'd take a matrix like this:
> O H L C
> 1
> 2
> 3
> 4
> 5
> ...
> N
>
> and output something like this to give to my SVM:
>
> O, H, L, C, C-1, C-2, C-3, etc
> 1
> 2
> 3
> 4
> 5
>
> obviously at the top of the matrix, the historical Close cells would be
> empty until there was enough data. In the pre-xts days, I accomplished this
> using sapply() and t(), a probably hackish solution, but all I was able to
> come up with. However, I am now running into problems with indices using
> this technique, and was wondering if there was a better way to perform this
> transformation, which really only amounts to a simple copy of data. Possible
> solutions that occur to me include some sort of "index shift" and then a
> merge, but I've been unable to get anything to work.
>
>
> --
> Aleks Clark
>
> [[alternative HTML version deleted]]
>
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