[R-SIG-Finance] [R-sig-finance] Garch problem

alexios alexios at 4dscape.com
Wed Mar 18 10:42:26 CET 2009


You could try to use a different distribution. For example, and using 
the rgarch package from r-forge:

spec=ugarchspec(variance.model=list(model="sGARCH", 
garchOrder=c(1,1)),mean.model=list(armaOrder=c(0,0),
include.mean=TRUE),distribution.model="std")

fit=ugarchfit(data, spec, solver="nlminb", control=list(trace=1))

This seems to converge, though with such little data I would be cautious 
in making predictions/inferences from the model.

-Alexios

Patrick Burns wrote:
> I was hoping to leave the "Doubtless" [1] as
> an exercise for the reader -- mainly as I'm not
> at all well versed in what is available in R for
> garch these days.
> 
> One idea would be to try a components model
> (may not be available).
> 
> Another idea would be to try a Bayesian estimate
> (may not be available).
> 
> A method that certainly is available is to pick a
> "reasonable" set of parameters (no estimation).
> 
> The course of action may well depend on the use
> to which the model is to be put.
> 
> [1] Stephen Crane "The Wayfarer"
> 
> Pat
> 
> 
> RON70 wrote:
>> Dear Patrick, thank you so much for this reply. You said one solution 
>> is to
>> increase the data point. However at this point I can not get more. 
>> Therefore
>> if you please tell more about "doubtless other paths" I will be truly
>> grateful.
>>
>> Regards,
>>
>>
>> Patrick Burns-2 wrote:
>>  
>>> The fit is essentially saying that the half-life
>>> of a shock is infinite.  This generally occurs
>>> when the in-sample volatility has a general
>>> trend.  One solution is more data.  There are
>>> doubtless other paths as well.
>>>
>>> RON70 wrote:
>>>    
>>>> I have following dataset as monthly percentage return for a stock :
>>>>
>>>> 0.173741362
>>>> -0.062237174
>>>>
>>>>         
>>> [ ... ]
>>>    
>>>> -0.001652893
>>>> -0.092301325
>>>>
>>>> Now I fit a GARCH (1,1) model on that :
>>>>
>>>>        
>>>>> garch(Delt(dat)[-1], c(1,1))
>>>>>             
>>>>  ***** ESTIMATION WITH ANALYTICAL GRADIENT *****
>>>>
>>>>      I     INITIAL X(I)        D(I)
>>>>
>>>>      1     4.331103e-03     1.000e+00
>>>>      2     5.000000e-02     1.000e+00
>>>>      3     5.000000e-02     1.000e+00
>>>>
>>>>     IT   NF      F         RELDF    PRELDF    RELDX   STPPAR   
>>>> D*STEP  NPRELDF
>>>>      0    1 -4.507e+02
>>>>      1    6 -4.508e+02  2.00e-04  3.20e-04  1.5e-03  6.3e+06  
>>>> 1.5e-04 1.01e+03
>>>>      2    7 -4.508e+02  1.57e-05  1.69e-05  1.4e-03  2.0e+00  
>>>> 1.5e-04 3.19e-01
>>>>      3   13 -4.521e+02  2.85e-03  4.72e-03  5.6e-01  2.0e+00  
>>>> 1.3e-01 3.16e-01
>>>>      4   16 -4.602e+02  1.76e-02  4.41e-03  8.1e-01  6.7e-01  
>>>> 5.1e-01 1.99e-02
>>>>      5   23 -4.607e+02  1.13e-03  2.77e-03  1.6e-04  7.4e+00  
>>>> 1.8e-04 8.48e+00
>>>>      6   24 -4.607e+02  4.81e-05  4.37e-05  1.6e-04  2.0e+00  
>>>> 1.8e-04 1.77e+01
>>>>      7   30 -4.638e+02  6.60e-03  8.81e-03  9.8e-02  2.0e+00  
>>>> 1.2e-01 1.84e+01
>>>>      8   31 -4.645e+02  1.52e-03  7.73e-03  8.2e-02  1.3e+00  
>>>> 1.2e-01 1.39e-02
>>>>      9   33 -4.688e+02  9.18e-03  6.28e-03  6.8e-02  0.0e+00  
>>>> 1.2e-01 6.94e-03
>>>>     10   35 -4.693e+02  9.32e-04  9.33e-04  8.9e-03  1.9e+00  
>>>> 1.8e-02 2.86e-02
>>>>     11   37 -4.699e+02  1.34e-03  1.59e-03  1.6e-02  1.8e+00  
>>>> 3.5e-02 5.99e-02
>>>>     12   38 -4.704e+02  1.05e-03  1.43e-03  1.6e-02  1.6e+00  
>>>> 3.5e-02 9.10e-03
>>>>     13   40 -4.705e+02  1.84e-04  2.85e-04  5.3e-03  1.2e+00  
>>>> 1.3e-02 7.52e-04
>>>>     14   42 -4.705e+02  3.71e-05  5.18e-05  2.4e-03  8.1e-01  
>>>> 5.0e-03 7.09e-05
>>>>     15   44 -4.705e+02  8.51e-07  3.04e-06  4.9e-04  8.2e-01  
>>>> 9.5e-04 5.29e-06
>>>>     16   57 -4.705e+02 -7.73e-15  1.09e-15  5.0e-15  4.4e+06  
>>>> 9.1e-15 2.87e-07
>>>>
>>>>  ***** FALSE CONVERGENCE *****
>>>>
>>>>  FUNCTION    -4.704848e+02   RELDX        4.961e-15
>>>>  FUNC. EVALS      57         GRAD. EVALS      16
>>>>  PRELDF       1.088e-15      NPRELDF      2.867e-07
>>>>
>>>>      I      FINAL X(I)        D(I)          G(I)
>>>>
>>>>      1    2.824235e-05     1.000e+00     5.619e+01
>>>>      2    8.649332e-02     1.000e+00    -5.899e-01
>>>>      3    9.175397e-01     1.000e+00    -6.866e-01
>>>>
>>>>
>>>> Call:
>>>> garch(x = Delt(dat)[-1], order = c(1, 1))
>>>>
>>>> Coefficient(s):
>>>>        a0         a1         b1  2.824e-05  8.649e-02  9.175e-01 
>>>> Warning message:
>>>> In sqrt(pred$e) : NaNs produced
>>>>
>>>> What we see that sum of alpha and beta coef is more than 1. Therefore
>>>> probably I choose a wrong model on my dataset. Can anyone please 
>>>> guide me
>>>> how to modify that model?
>>>>
>>>> Regards,
>>>>
>>>>       
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>>>     
>>
>>
> 
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