[R-SIG-Finance] ARIMA question
Jeff Ryan
jeff.a.ryan at gmail.com
Wed Nov 7 22:17:28 CET 2007
Do you have a particular version? Mine does not have a method like that...
> x.model
Call:
arima(x = x, order = c(0, 0, 2))
Coefficients:
ma1 ma2 intercept
0.3812 -0.1138 0.0936
s.e. 0.0956 0.0862 0.2631
sigma^2 estimated as 4.318: log likelihood = -215.15, aic = 438.31
> class(x.model)
[1] "Arima"
> methods(fitted)
[1] fitted.default* fitted.isoreg* fitted.nls*
[4] fitted.quantmod* fitted.smooth.spline* fitted.values.quantmod*
Non-visible functions are asterisked
> fitted(x.model)
NULL
>
On Nov 7, 2007 3:07 PM, Nathan Bryant <nbryant at optonline.net> wrote:
>
> There is a method called "fitted()" that applies to most model classes
> including Arima, which does the same thing.
>
>
> Jeff Ryan wrote:
> > I think it is as simple as backing out from the residuals:
> >
> > # an MA2 model
> > x <- arima.sim(list(ma=2),n=100)
> >
> > #Fitted as such...
> > x.model <- arima(x,c(0,0,2))
> >
> > # add the residuals to the original data
> > x.insample.fit <- x-residuals(x.model)
> >
> > # and you can even see them:
> > plot(x)
> > par(new=TRUE)
> > lines(x.insample.fit,col=3,lty=2)
> >
> > Jeff
> >
> >
> > On Nov 7, 2007 12:47 PM, Yalla, Swaroop (FID)
> > <Swaroop.Yalla at morganstanley.com> wrote:
> >
> >> Hi:
> >>
> >> I have another ARIMA question for R. I was finally able to use ARIMA
> >> modeling on my data. Now to forecast out of sample, we can use
> >> predict(fit, n.ahead = 10) type of command and thats fine- but how can I
> >> see the fit in-sample. I mean is there a easy way to just compare the
> >> actual data with the fitted model in-sample?
> >>
> >> thanks for all the help..
> >> Swaroop
> >> --------------------------------------------------------
> >>
> >> This is not an offer (or solicitation of an offer) to bu...{{dropped:24}}
> >>
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