Rich,

If your data frame is called df, try

row.names(df) <- df$sampdate

Jean


On Thu, Jun 19, 2014 at 5:07 PM, Rich Shepard <rshepard@appl-ecosys.com>
wrote:

>   I recall reading how to do this somewhere, but I cannot find just where I
> read it. I have compositional data frames of this format:
>
>     sampdate filter gather  graze predate  shred
> 1 2000-07-18 0.0550 0.5596 0.0734  0.2294 0.0826
> 2 2003-07-08 0.0734 0.6147 0.0183  0.2294 0.0642
> 3 2005-07-13 0.1161 0.5714 0.0357  0.1696 0.1071
> 4 2006-06-28 0.1000 0.4667 0.1500  0.1333 0.1500
> 5 2010-09-14 0.0778 0.6111 0.0444  0.1889 0.0778
> 6 2011-07-13 0.0879 0.5714 0.0659  0.2747 0.0000
> 7 2012-07-11 0.1042 0.5313 0.0625  0.2396 0.0625
>
> and the sampdate column should be the row headings rather than the numeric
> sequence seen above. What is the command to move the sampdates to row
> headers?
>
> Rich
>
> ______________________________________________
> R-help@r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/
> posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>

	[[alternative HTML version deleted]]

