You get what you wanted from

do.call(plot,list(x=quote(x),y=quote(y)))

By the time do.call() gets the arguments it doesn't know how y was
originally computed, just what values it has.

   -thomas


On Thu, Mar 27, 2014 at 6:17 PM, Rolf Turner <r.turner@auckland.ac.nz>wrote:

>
>
> I was under the impression that
>
>         do.call(foo,list(x=x,y=y))
>
> should yield the same result as
>
>         foo(x,y).
>
> However if I do
>
>         x <- 1:10
>         y <- (x-5.5)^2
>         do.call(plot,list(x=x,y=y))
>
> I get the expected plot but with the y-values (surrounded by c()) being
> printed (vertically) in the left-hand margin of the plot.
>
> The help for do.call() says:
>
>  The behavior of some functions, such as substitute, will not be the
>> same for functions evaluated using do.call as if they were evaluated
>> from the interpreter. The precise semantics are currently undefined and
>> subject to change.
>>
>
> Am I being bitten by an instance of this phenomenon?  Seems strange.
>
> I would be grateful for enlightenment.
>
> cheers,
>
> Rolf Turner
>
> ______________________________________________
> R-help@r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/
> posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>



-- 
Thomas Lumley
Professor of Biostatistics
University of Auckland

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