I actually solved the problem in a backhanded (backslashed?) sort of
way...took out the quotation marks in the original file.  All is well.
Thanks!


On Sun, Nov 17, 2013 at 4:38 PM, Rolf Turner <r.turner@auckland.ac.nz>wrote:

>
> (1) The backslashes are not really there; they are an artefact of the R
> print() function.
> Try cat(u,"\n").  I think this might be an FAQ.
>
> (2) Is not your problem the fact that your are setting "replacement" equal
> to the
> thing you are trying to get rid of?  I.e. don't you want
>
>     v <- gsub(pattern='\"',replacement='',x=u)     ???
>
> Either I am misunderstanding your intent or you need another cup of coffee.
>
>     cheers,
>
>     Rolf
>
>
> On 11/18/13 11:07, Erin Hodgess wrote:
>
>> Dear R People:
>>
>> I'm sure that this is a very simple problem, but I have been wresting with
>> it for some time.
>>
>> I have the following file that has the following one line:
>>
>>   CRS("+init=epsg:28992")
>>
>> Fair enough.  I scan it into R and get the following:
>>
>>  u
>>>
>> [1] "CRS(\"+init=epsg:28992\")"
>>
>>> gsub(pattern='\"',replacement='"',x=u)
>>>
>> [1] "CRS(\"+init=epsg:28992\")"
>>
>> I need to get rid of the extra quotation marks and slashes.  I've tried
>> all
>> sorts of things, including gsub, as you see,  but no good.
>>
>


-- 
Erin Hodgess
Associate Professor
Department of Computer and Mathematical Sciences
University of Houston - Downtown
mailto: erinm.hodgess@gmail.com

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