Thanks.

I converted my data structure( that is most of the confusion in my case ) 
into a data frame and then applied this function

y <- apply( y, 1, function(z) str_extract(z,"Current.*?[/|]"))

to get

"Current Usage : init:2359296, used:15857920, committed:15892480, 
max:50331648|"

Mohan



From:   jim holtman <jholtman@gmail.com>
To:     mohan.radhakrishnan@polarisft.com
Cc:     R mailing list <r-help@r-project.org>
Date:   11/01/2013 05:17 PM
Subject:        Re: [R] Replace element with pattern



try this:

> x <- rbind("Peak Usage    : init:2359296, used:15859328, 
committed:15892480,max:50331648Current Usage : init:2359296, 
used:15857920,committed:15892480, max:50331648|-------------------|")
> apply(x, 1, function(a) sub("(Current.*?[/|]).*", "\\1", a))
[1] "Peak Usage    : init:2359296, used:15859328,
committed:15892480,max:50331648Current Usage : init:2359296,
used:15857920,committed:15892480, max:50331648|"
>
>

Jim Holtman
Data Munger Guru

What is the problem that you are trying to solve?
Tell me what you want to do, not how you want to do it.


On Fri, Nov 1, 2013 at 4:09 AM,  <mohan.radhakrishnan@polarisft.com> 
wrote:
> Hi,
>          I have a data frame with one column and several rows of the 
form.
>
> "Peak Usage    : init:2359296, used:15859328, committed:15892480,
> max:50331648Current Usage : init:2359296, used:15857920,
> committed:15892480, max:50331648|-------------------|"
>
> I tested the regex
>
>  Current.*?[\|]
>
> in an online tester which greedily matches upto the first 'pipe' 
character
>
> Current Usage : init:2359296, used:15857920, committed:15892480,
> max:50331648|
>
> This is what I want.
>
> I tried to replace the entire rows using
>
> apply( y, 1, function(x) gsub(x,"Current.*?[/|]",x)) which didn't work.
>
> How is this done ? I also want to recursively apply some more patterns 
one
> by one on the rows till I reduce it to exactly what I want. Is there a 
way
> to do this without loops ?
>
> Thanks,
> Mohan
>
>
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