Hi Arun,

Sorry for late reply.

I would like to thank you for your pointer. This is what I wanted. Thanks
for your help.

Thanks and regards,


On Sun, Oct 27, 2013 at 10:33 PM, arun <smartpink111@yahoo.com> wrote:

> Hi,
> DF$Col2
> # [1] a e b b a b c e b a c c e e a c d c c e
> #Levels: a b c d e
>
>
> "b" is not found in any of the "Grs".  Also Gr3 is not presnt in DF$Col2
>
> So, I am not sure whether this works for you.
>
> indx <- 1+ 2*DF$Col2 %in% Gr1 + 4*DF$Col2 %in% Gr2 + 8*DF$Col2 %in% Gr3
>  indx <- indx[indx>1]
>  split(DF[DF$Col2%in% c(Gr1,Gr2,Gr3),],indx)
>
> A.K.
>
>
>
>
>
> On Sunday, October 27, 2013 11:19 AM, Christofer Bogaso <
> bogaso.christofer@gmail.com> wrote:
> Hi again,
>
> Let say I have following DF:
>
> DF <- structure(list(Col1 = 1:20, Col2 = structure(c(1L, 5L, 2L, 2L,
> 1L, 2L, 3L, 5L, 2L, 1L, 3L, 3L, 5L, 5L, 1L, 3L, 4L, 3L, 3L, 5L
> ), .Label = c("a", "b", "c", "d", "e"), class = "factor")), .Names =
> c("Col1",
> "Col2"), row.names = c(NA, -20L), class = "data.frame")
>
> DF
>
>
> Now I create 3 groups like:
>
> Gr1 <- c('a', 'c', 'd')
> Gr2 <- c('e')
> Gr3 <- c('f', 'x')
>
>
> My goal is to split DF according to these groups. And to generate NULL (or
> something like that) if a particular group contains no value.
>
> So far I tried to split DF according to split() function. However it looks
> to me like, this split() does not offer this kind of customization.
>
>
> Can someone here help me how to split my data.frame according to this
> criteria?
>
> Thanks and regards,
>
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>
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