Thanks.
Yes it was due to the factor-thing. If I change Genotype as mentioned
everything works fine.
Thanks
Hermann


2013/10/15 Sarah Goslee <sarah.goslee@gmail.com>

> Hi,
>
> Genotype is a factor, and R is giving you the default type for that data
> type.
>
> I changed your data frame to mydata because df() is a function, but see
> this:
>
> > str(mydata)
> 'data.frame':    20 obs. of  2 variables:
>  $ Genotype: Factor w/ 3 levels "0","1","2": 1 1 1 1 1 1 1 1 2 2 ...
>  $ z       : num  0.0703 2.1574 0.514 0.4873 0.1558 ...
>
> It sounds like you might want:
>
> with(mydata, plot(as.numeric(as.character(Genotype)), z))
>
> but if Genotype is best represented as a factor, that may not be the
> most informative type of plot.
>
> Sarah
>
> On Tue, Oct 15, 2013 at 10:23 AM, Hermann Norpois <hnorpois@gmail.com>
> wrote:
> > Hello,
> >
> > I would like to plot some values referring to the genotype (which is 0,1
> > and 2).  My data is organised like this:
> >
> > head (df)
> >   Genotype          z
> > 1        0 0.07029379
> > 2        0 2.15739115
> > 3        0 0.51395897
> > 4        0 0.48733029
> > 5        0 0.15584074
> > 6        0 0.27755294
> >
> > I tried:
> >> plot (df)
> > And.
> >> plot (z ~ Genotype, data=df)
> >
> > But it is always the same. As demonstrated in the attachment there are
> bars
> > with mean etc... But I want dots only. How does this work?
> >
> > Thanks
> > Hermann
> >
> >> dput (df)
> > structure(list(Genotype = structure(c(1L, 1L, 1L, 1L, 1L, 1L,
> > 1L, 1L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 3L, 3L), .Label = c("0",
> > "1", "2"), class = "factor"), z = c(0.0702937908415368, 2.15739115226985,
> > 0.513958971085714, 0.487330287677455, 0.155840743875606,
> 0.277552938739661,
> > 0.507384510251828, 9.25159831317385e-05, 0.420814150642641,
> > 10.628270981371,
> > 0.518650521289299, 0.644448203670876, 0.133539811585953,
> 0.248985608185673,
> > 0.152636019877717, 0.00964805339859479, 7.57036184259711e-05,
> > 0.649435257991169, 0.38951827610564, 75.6011068681301)), .Names =
> > c("Genotype",
> > "z"), row.names = c(NA, 20L), class = "data.frame")
> >>
>
> --
> Sarah Goslee
> http://www.functionaldiversity.org
>

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