Thanks.  That's not quite what I'm looking for, but it's good see different
ways to slice and dice data.

In my example, the one duplicated x,y pair would 9,9, so I would want to
reduce the original list to

> xyz
$x
 [1] 8 6 9 0 0 3 9 7 1
$y
 [1] 1 2 9 5 1 2 0 9 2
$z
 [1] 5 6 9 0 5 1 1 7 3

and if it were also possible to get the xyz values that were removed that
would be perfect.  e.g.

$x
[1] 9
$y
[1] 9
$z
[1] 4

Does that make sense?

(my data is in a form accepted by the deldir package, fwiw)

Best,

R.



On Wed, Oct 9, 2013 at 9:56 AM, arun <smartpink111@yahoo.com> wrote:

>
>
> Hi,
>
> Not sure about your expected output.
>
> xyz<-
> list(x=c(8,6,9,0,0,3,9,7,1,9),y=c(1,2,9,5,1,2,0,9,2,9),z=c(5,6,9,0,5,1,1,7,3,4))
> indx<-sort(unique(unlist(lapply(xyz[1:2],function(u)
> which(!duplicated(u))),use.names=FALSE)))
>  xyz[1:2]<-lapply(xyz[1:2],function(u) u[!duplicated(u)])
>  xyz[3]$z<- xyz[3]$z[indx]
>  xyz
> #$x
> #[1] 8 6 9 0 3 7 1
> #
> #$y
> #[1] 1 2 9 5 0
> #
> #$z
> #[1] 5 6 9 0 1 1 7 3
>
> A.K.
>
>
> New to R here.  Lots of fun.  Still rather green though.
>
> I'd like to select unique items from a list that looks like this (for
> example):
>
> > xyz
> $x
>  [1] 8 6 9 0 0 3 9 7 1 9
> $y
>  [1] 1 2 9 5 1 2 0 9 2 9
> $z
>  [1] 5 6 9 0 5 1 1 7 3 4
>
> I'd like to select unique (x,y), while preserving association with z
> values.  When there are duplicate (x,y) pairs, it doesn't really matter
> which (x,y,z) triplet gets preserved - selecting the first would be fine,
> but any other way to do it would be fine also.  It /would/ be handy to also
> get a list of the rejected triplets, if that's possible.  Ideas?
>
> Thanks!
>
> R
>
> ______________________________________________
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> PLEASE do read the posting guide
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> and provide commented, minimal, self-contained, reproducible code.
>



-- 
-Ron-

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