Wonderful!

Thank you Arun!

Irene
 
Irene Ruberto




________________________________
 Da: arun kirshna [via R] <ml-node+s789695n4677558h52@n4.nabble.com>

Inviato: Giovedì 3 Ottobre 2013 22:51
Oggetto: Re: String substitution



Hi, 
Try: 
dat$y<- as.character(dat$y) 
dat1<- dat 
dat2<- dat 
library(stringr) 
 dat$y[NET]<- substr(word(dat$y[NET],2),1,1) 
 dat$y 
#[1] "n"     "n"     "house" "n"     "tree" 

#or 
for(i in 1:length(NET)){dat1$y[NET[i]]<- "n"} 
 dat1$y 
#[1] "n"     "n"     "house" "n"     "tree" 
#or 
dat2$y[NET]<- gsub(".*(n).*","\\1",dat2$y[NET]) 
 dat2$y 
#[1] "n"     "n"     "house" "n"     "tree" 


A.K. 


Hello, 

I am trying to replace strings containing a certain word, I 
first identified the word (in this example "net") with grep, and then I 
need to replace those string with "n". It should be very simple but I 
don't seem to find the solution. 
  
Example: 

x<-c(5:9) 
y<- c("with net", "with nets", "house", "no nets", "tree") 
dat<-as.data.frame(cbind(x, y) ) 
NET<-grep("net", dat$y) 

# I want y to become ("n", "n", "house", "n", "tree") # 

# I have tried several ways including the following but without success # 

for (i in 1: length(NET)) { 
dat$y[NET[i]]<- "n" } 


Thank you for your help! 

______________________________________________ 
[hidden email] mailing list 
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code. 


________________________________

If you reply to this email, your message will be added to the discussion below:http://r.789695.n4.nabble.com/String-substitution-tp4677541p4677558.html 
To unsubscribe from String substitution, click here.
NAML



--
View this message in context: http://r.789695.n4.nabble.com/String-substitution-tp4677541p4677612.html
Sent from the R help mailing list archive at Nabble.com.
	[[alternative HTML version deleted]]

