Hi,

or ... a shorter way would be:

a1<-c(1,2,3,4,5,1,2,3,1,1,1,2,3,4,5,1,2,3)

a1[c(which(diff(a1)!=1),length(a1))]

Hope it helps.

Marion

---------- Forwarded message ----------
From: arun <smartpink111@yahoo.com>
Date: 2013/5/29
Subject: Re: [R] Obtaing the maximum
To: R help <r-help@r-project.org>


Hi,
May be this helps:
a1<-c(1:5,1:3,rep(1,2),1:5,1:3)
 a1
# [1] 1 2 3 4 5 1 2 3 1 1 1 2 3 4 5 1 2 3


a1[sort(c(which(c(diff(a1)<0,TRUE)), which(a1[-length(a1)] == a1[-1])))]
#[1] 5 3 1 1 5 3
a2<-c(1:2,rep(1,4),1:7,1:3)
a2
# [1] 1 2 1 1 1 1 1 2 3 4 5 6 7 1 2 3
 a2[sort(c(which(c(diff(a2)<0,TRUE)), which(a2[-length(a2)] == a2[-1])))]
#[1] 2 1 1 1 1 7 3

a3<-c(c(1,4,5,8),rep(1,3),c(1,8,11,13),1:4)
 a3
# [1]  1  4  5  8  1  1  1  1  8 11 13  1  2  3  4
 a3[sort(c(which(c(diff(a3)<0,TRUE)), which(a3[-length(a3)] == a3[-1])))]
#[1]  8  1  1  1 13  4

 a4<-c(c(1,4,5,8),rep(4,3),c(1,8,11,13),8:12)
 a4
# [1]  1  4  5  8  4  4  4  1  8 11 13  8  9 10 11 12
a4[sort(c(which(c(diff(a4)<0,TRUE)), which(a4[-length(a4)] == a4[-1])))]
#[1]  8  4  4  4 13 12
A.K.



>Hi all, I have a series whose tpe for that is like series I expose below.
>
>The thing is if a incremental number ends I´m in the first "type" of event
>in this success is named 5 (because of the maximum is 5). In the series I
>have this kind of events  5,3,1,1,5,3
>
>But I don´t know extactly a priori what is the maximum and when "stops"
>there is some function in r doing something similar this?
>
>Thans in advance to all.
>
>
>1
>2
>3
>4
>5
>1
>2
>3
>1
>1
>1
>2
>3
>4
>5
>1
>2
>3

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-- 
Mag.a Marion Wenty
Wissenschaftliche Mitarbeiterin
Institut für Kinderrechte und Elternbildung
Ballgasse 2, 6. Stock
1010 Wien

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