Dear Milan and other users,

Thank you for your help, it worked. The problem is that the function "do.call" is not ready for vectors and I need it in order to integrate it afterwards.

With the pweibull, I can write:
pweibull(1,shape=1)
pweibull(2,shape=1)
pweibull(1:2,shape=1)

When I do the same with the do.call, I obtain an error:
do.call("pweibull",c(q=1,list(shape=1,scale=1)))
do.call("pweibull",c(q=2,list(shape=1,scale=1)))
do.call("pweibull",c(q=1:2,list(shape=1,scale=1)))
Error in pweibull(q1 = 1L, q2 = 2L, shape = 1, scale = 1) : 
  unused argument(s) (q1 = 1, q2 = 2)

Do you know how can I solve it?

Thank you, 
Oleguer


On 03/03/2013, at 20:32, Milan Bouchet-Valat <nalimilan@club.fr> wrote:

> Le dimanche 03 mars 2013 à 19:49 +0100, Oleguer Plana Ripoll a écrit :
>> Hello everyone,
>> 
>> I have a quick question but I am stuck with it and I do not know how
>> to solve it.
>> 
>> Imagine I need the distribution function of a Weibull(1,1) at t=3,
>> then I will write pweibull(3,1,1).
>> 
>> I want to keep the shape and scale parameters in a list (or a vector
>> or whatever). Then I have
>> parameters<-list(shape=1,scale=1) 
>> but when I write pweibull(3,parameters) I get the following error:
>> Error in pweibull(q, shape, scale, lower.tail, log.p) : 
>>  Non-numeric argument to mathematical function
>> 
>> I have to write pweibull(3,parameters[[1]],parameters[[2]]) but I am
>> very interested in being able to write pweibull(3,parameters).
>> 
>> Does anyone know how to solve it?
> What you are looking for is do.call():
> 
> parameters <- list(q=3, shape=1, scale=1)
> do.call("pweibull", parameters)
> 
> or
> 
> parameters <- list(shape=1, scale=1)
> do.call("pweibull", c(q=3, parameters))
> 
> 
> Regards
> 
>> Thank you very much,
>> 
>> Oleguer Plana
>> 	[[alternative HTML version deleted]]
>> 
>> ______________________________________________
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>> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
>> and provide commented, minimal, self-contained, reproducible code.
> 


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