Hi,
thank you. I just came up with

lapply(c(1:length(lst)), function(x) return(lst[[x]][[2]]))


but your solution is much more elegant. Although I don't completely understand: if lst is the argument of function x[[2]] this should be iterpreted as lst[[2]]. Where am I wrong?
Björn


Am 11.01.2013 15:44, schrieb arun kirshna [via R]:
> Hi,
> Try this:
>  lapply(lst,function(x) x[[2]])
> #or
> lst1<-lapply(lst,function(x) {names(x)<-1:3;x})
>  lapply(lst1,function(x) x$`2`)
> #[[1]]
> #[1] 1 2 3
>
> #[[2]]
> #[1] 4 5 6
>
> A.K.
>
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-- 
Björn Helm
Institut für Siedlungs- und Industriewasserwirtschaft
Technische Universität Dresden
D-01062 Dresden

Tel: +49 (0) 351 463 34616
Fax: +49 (0) 351 463 37204

http://tu-dresden.de/hydro/siedlungswasserwirtschaft





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