Ok,I'll follow your suggestion.
Thanks!







At 2012-12-31 11:20:17,arun <smartpink111@yahoo.com> wrote:
>HI Meng,
>
>
>Just try:
>rep(z,rach=nrow(dat))
>#[1]   0.1  10.0 100.0
> rep(z,chair=nrow(dat))
>#[1]   0.1  10.0 100.0
>rep(z,times=nrow(dat))
>#[1]   0.1  10.0 100.0   0.1  10.0 100.0   0.1  10.0 100.0
> rep(z,each=nrow(dat))
>#[1]   0.1   0.1   0.1  10.0  10.0  10.0 100.0 100.0 100.0
> rep(z,nrow(dat))
>#[1]   0.1  10.0 100.0   0.1  10.0 100.0   0.1  10.0 100.0
>
>#and
>dat*rep(z,times=nrow(dat))
> #    x1    x2    x3
>#1   0.1   0.4   0.7
>#2  20.0  50.0  80.0
>#3 300.0 600.0 900.0
> dat*rep(z,nrow(dat))
>#     x1    x2    x3
>#1   0.1   0.4   0.7
>#2  20.0  50.0  80.0
>#3 300.0 600.0 900.0
>dat*rep(z,each=nrow(dat))
>#   x1 x2  x3
>#1 0.1 40 700
>#2 0.2 50 800
>#3 0.3 60 900
>
>A.K.
>
>
>
>
>----- Original Message -----
>From: meng <laomeng_3@163.com>
>To: Andrius Druzinis <andrius.druzinis@gmail.com>
>Cc: R help <r-help@r-project.org>
>Sent: Sunday, December 30, 2012 9:24 PM
>Subject: Re: [R] How to multiple the vector and variables from dataframe
>
>Hi Andrius:
>Thanks for your reply.
>Your answer: dat*rep(z,each=nrow(dat)) works well.
>
>But a strange thing happened:
>dat<-data.frame(x1=1:3,x2=4:6,x3=7:9)
>z<-c(0.1,10,100)
>#I wanna 0.1*x1,10*x2,100*x3
>
>I type:
>dat*rep(z,rach=nrow(dat))
>"rach" is "each" indeed,but I type "rach" mistakenly.
>What's strange to me is :No error reply appears,but show me the result:
>> dat*rep(z,rach=nrow(dat))
>     x1    x2    x3
>1   0.1   0.4   0.7
>2  20.0  50.0  80.0
>3 300.0 600.0 900.0
>Why does it happen,and what "rach" means?
>
>Many thanks.
>
>
>
>
>
>
>
>
>
>
>At 2012-12-31 00:08:26,"Andrius Druzinis" <andrius.druzinis@gmail.com> wrote:
>
>Hi Meng, 
>
>
>A one-liner would be
>dat*rep(z, each=nrow(dat))
>
>
>Cheers, 
>Andrius
>
>
>
>2012/12/30 meng <laomeng_3@163.com>
>hi all:
>Here's a dataframe(dat) and a vector(z):
>
>dat:
>x1     x2    x3
>0.2   1.2   2.5
>0.5   2      5
>0.8   3      6.2
>
>> z
>[1]  10 100 100
>
>I wanna do the following:
>10*x1,100*x2,1000*x3
>
>My solution is using the loop for z and dat(since the length of z is the same as ncol  of dat),which is tedious.
>I wanna an efficient solution to do it .
>
>Any help?
>
>Many thanks!
>
>My best
>
>
>
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>
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>
>
>
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>
>______________________________________________
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>PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
>and provide commented, minimal, self-contained, reproducible code.
>

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