?findInterval


On Thu, Dec 6, 2012 at 3:00 PM, Jonathan Greenberg <jgrn@illinois.edu>wrote:

> Folks:
>
> Say I have a set of histogram breaks:
>
> breaks=c(1:10,15)
>
> # With bin ids:
>
> bin_ids=1:(length(breaks)-1)
>
> # and some data (note that some of it falls outside the breaks:
>
> data=runif(min=1,max=20,n=100)
>
> ***
>
> What is the MOST EFFICIENT way to "classify" data into the histogram bins
> (return the bin_ids) and, say, return NA if the value falls outside of the
> bins.
>
> By classify, I mean if the data value is greater than one break, and less
> than or equal to the next break, it gets assigned that bin's ID (note that
> length(breaks) = length(bin_ids)+1)
>
> Also note that, as per this example, the bins are not necessarily equal
> widths.
>
> I can, of course, cycle through each element of data, and then move through
> breaks, stopping when it finds the correct bin, but I feel like there is
> probably a faster (and more elegant) approach to this.  Thoughts?
>
> --j
>
>
>
>
>
> --
> Jonathan A. Greenberg, PhD
> Assistant Professor
> Department of Geography and Geographic Information Science
> University of Illinois at Urbana-Champaign
> 607 South Mathews Avenue, MC 150
> Urbana, IL 61801
> Phone: 217-300-1924
> AIM: jgrn307, MSN: jgrn307@hotmail.com, Gchat: jgrn307, Skype: jgrn3007
>
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-- 
Gregory (Greg) L. Snow Ph.D.
538280@gmail.com

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