On Sat, Nov 3, 2012 at 4:08 PM, Alexander Shenkin <ashenkin@ufl.edu> wrote:

> On 11/2/2012 5:14 PM, Gabor Grothendieck wrote:
> > On Fri, Nov 2, 2012 at 6:02 PM, Alexander Shenkin <ashenkin@ufl.edu>
> wrote:
> >> Hi Folks,
> >>
> >> I'm trying to extract just the backreferences from a regex.
> >>
> >>> temp = "abcd1234abcd1234"
> >>> regmatches(temp, gregexpr("(?:abcd)(1234)", temp))
> >> [[1]]
> >> [1] "abcd1234" "abcd1234"
> >>
> >> What I would like is:
> >> [1] "1234" "1234"
> >>
> >> Note: I know I can just match 1234 here, but the actual example is
> >> complicated enough that I have to match a larger string, and just want
> >> to pass out the backreferenced portion.
> >>
> >> Any help greatly appreciated!
> >>
> >
> > Try this:
> >
> >> library(gsubfn)
> >> strapplyc(temp, "abcd(1234)")
> > [[1]]
> > [1] "1234" "1234"
> >
>
> Thanks Gabor.  Didn't find strapplyc in package gsubfun, but did find
> strapply, and that worked well.
>


You must have an old version of the package.  Time to upgrade.

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