If you are after all the possible percentages with two decimal places, why don't you use this:

seq(from=0, to=100, by=.01)/100

I'm not really sure what you are trying to do in terms of rows and columns, however.  Can you be a bit more specific on what each row/column is?  
Are you trying to group the numbers so that all the entries in a row add up to 100% and then, once it does, split the following entries onto the next row until they add up to 100%, etc.?
Thanks.



________________________________
 From: wwreith <reith_william@bah.com>
To: r-help@r-project.org 
Sent: Friday, October 12, 2012 10:30 AM
Subject: [R] Autofilling a large matrix in R

I wish to create a matrix of all possible percentages with two decimal place
percision. I then want each row  to sum to 100%. I started with the code
below with the intent to then subset the data based on the row sum. This
works great for 2 or 3 columns, but if I try 4 or more columns the number of
rows become to large. I would like to find a way to break it down into some
kind of for loop, so that I can remove the rows that don't sum to 100%
inside the for loop rather than outside it. My first thought was to take
list from 1:10, 11:20, etc. but that does not get all of the points. 

g<-as.matrix(expand.grid(rep(list(1:100), times=3)))

Any thoughts how to split this into pieces?



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