
Dear Arun and Barradas,
millions of thanks. you guys always rock.
regards
eliza

> Date: Fri, 5 Oct 2012 14:41:38 -0700
> From: smartpink111@yahoo.com
> Subject: Re: [R] loop for column substraction of a matrix
> To: eliza_botto@hotmail.com
> CC: ruipbarradas@sapo.pt; r-help@r-project.org
> 
> Hi,
> 
> Sorry, I think I misunderstand your question (after reading Rui's solution).
> 
> You can also try any of these to get the result if this is what you meant:
> set.seed(1)
> mat1<-matrix(sample(1:500,380,replace=TRUE),ncol=38)
> res1<-t(do.call(rbind,lapply(1:ncol(mat1), function(i) mat1[,i]-apply(mat1,1,sum))))
> #or
> res1<-sapply(1:ncol(mat1), function(i) mat1[,i]-apply(mat1,1,sum))
> #or
> res1<-mapply(FUN=function(i) mat1[,i]-rowSums(mat1), 1:ncol(mat1))
> A.K  
> 
> 
> 
> 
> 
> ----- Original Message -----
> From: eliza botto <eliza_botto@hotmail.com>
> To: "r-help@r-project.org" <r-help@r-project.org>
> Cc: 
> Sent: Friday, October 5, 2012 4:05 PM
> Subject: [R] loop for column substraction of a matrix
> 
> 
> Dear useRs,
> 
> 
> I have a matrix with 38 columns and 365 rows. what i want to do is the following.....
> 
> 1. subtracting from each column, first itself and then all the remaining columns. More precisely, from column number 1, i will first subtract itself(column 1) and then the remaining 37 columns. Afterwards i will take column number 2 and do the same. In this way i want to proceed till 38th column. 
> 2. i want to print the resulting matrix on A4 paper.
> 
> Bundle of thanks in advance.
> 
> best regards
> eliza
> 
> 
>                           
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