Bert,

Is it important that you end up with a data frame?  If not, it would be 
very easy to generate a list with the unique values for each column.  For 
example:

df <- data.frame(v1 = sample(5, 20, T), v2 = sample(7, 20, T), 
        v3 = sample(9, 20, T), v4 = sample(11, 20, T))
lapply(df, unique)

Jean


"Bert Jacobs" <bert.jacobs@figurestofacts.be> wrote on 07/20/2012 02:37:37 
PM:

> Hi,
> 
> I was wondering what the best way is to create a new dataframe based on 
an
> existing dataframe with only the unique available levels for each column 
(22
> columns in total) in it.
> 
> If some columns have less unique values than others, then those columns 
can
> be filled with blanks for the remaining part. Is it possible to make it 
a
> generic function, which is independent from the column names?
> 
> Thx for helping me out.
> 
> 
> 
> Kind regards,
> 
> Bert

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