Hi,
Thanks a lot for answer. It is what I mean.
But the code does not seem to work (


Le Jul 19, 2012 à 8:52 AM, Petr Savicky [via R] a écrit :

> On Wed, Jul 18, 2012 at 06:02:27PM -0700, bilelsan wrote: 
> > Leave the Taylor expansion aside, how is it possible to compute with [R]: 
> > f(e) = e1 + e2 #for r = 1 
> > + 1/2!*e1^2 + 1/2!*e2^2 + 1/2!*e1*e2 #for r = 2, excluding e2*e1 
> > + 1/3!*e1^3 + 1/3!*e1^2*e2 + 1/3!*e2^2*e1 + 1/3!*e2^3 #for r = 3, excluding 
> > e2*e1^2 and e1*e2^2 
> > + ... #for r = k 
> > In other words, I am trying to figure out how to compute all the possible 
> > combinations as exposed above. 
> 
> Hi. 
> 
> For a general r, do you mean the following sum of products? 
> 
>   1/r! (e1^r + e1^(r-1) e2 + ... e1 e2^(r-1) + e2^r) 
> 
> If this is correct, then try 
> 
>   f <- 0 
>   for (r in 1:k) { 
>      f <- f + 1/factorial(r) * sum(e1^(r:0)*e2^(0:r)) 
>   } 
> 
> Hope this helps. 
> 
> Petr Savicky. 
> 
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