Thanks,
Y

On Fri, Jul 20, 2012 at 1:02 PM, arun <smartpink111@yahoo.com> wrote:

> Hi,
>
> Try this:
> dat1<-read.table(text="
>        id    date        a        b      c        y
> 1      1 8/6/2008    Red    15    B          22
> 2      1 8/6/2008  Green  15    B          22
> ",sep="",header=TRUE)
>  dat1$date<-with(dat1,as.factor(date))
>  dat1
>   id     date     a  b c  y
> 1  1 8/6/2008   Red 15 B 22
> 2  1 8/6/2008 Green 15 B 22
>  is.factor(dat1$date)
> [1] TRUE
> A.K.
>
>
>
> ----- Original Message -----
> From: Yolande Tra <yolande.tra@gmail.com>
> To: r-help@r-project.org
> Cc:
> Sent: Friday, July 20, 2012 10:44 AM
> Subject: [R] convert date to a factor
>
> Hello,
>
> I would like to convert date as a factor to represent time in a repeated
> measure situation in the following code. How would I do that?
> >  d <- read.csv(file.path(dataDir,"data.csv"), as.is=T,stringsAsFactors =
> FALSE)
> > d[1:2,]
>         id     date         a        b      c         y
> 1       1 8/6/2008     Red    15     B          22
> 2       1 8/6/2008   Green   15     B          22
> Thank you,
> Y
>
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>
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> PLEASE do read the posting guide
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> and provide commented, minimal, self-contained, reproducible code.
>
>

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