oh, thank you very much!



________________________________
 From: Michael Weylandt [via R] <ml-node+s789695n4630027h85@n4.nabble.com>
To: christy <saunders.christy@ymail.com> 
Sent: Tuesday, May 15, 2012 12:28 AM
Subject: Re: how to create a new data given a vector of variable names


I think you're making this too hard: 

x[, vars] 

should do it. 

For a smaller example, consider 

x <- data.frame(a = 1:5, b = rnorm(5), c = letters[1:5]) 

x[, c("b","a")] 

Best, 
Michael 

On Tue, May 15, 2012 at 1:12 AM, christy <[hidden email]> wrote: 

> hi, please help me on this. I'm very new to R.  I've been figuring out how to 
> do this the whole day, and I could not get the correct R code. 
> 
> Suppose I have a dataframe called x and it consists of 10variables. 
> 
>>x 
> 
>          h 1        h 2        h 3         h 4        h 5        h 6 
> h 7        h 8        h 9 
> 1  0.38971928 0.62884802 0.32708216 0.093909834 0.57773251 0.41258918 
> 0.37360577 0.65259411 0.88204799 
> 2  0.51890830 0.15949863 0.75715149 0.871781822 0.06321826 0.91844114 
> 0.05692871 0.84588084 0.77173376 
> 3  0.94057256 0.16100731 0.80961141 0.239716639 0.55804412 0.42854829 
> 0.54987115 0.68416629 0.24353692 
> 4  0.19895720 0.52955693 0.98471869 0.378197899 0.16774788 0.68029534 
> 0.42039730 0.82217244 0.74397124 
> 5  0.27899679 0.29145024 0.07198476 0.732466508 0.14887818 0.90658800 
> 0.64186885 0.66542828 0.98182923 
> 6  0.69375077 0.05840897 0.77325437 0.866099979 0.75063858 0.94230759 
> 0.72182389 0.65574673 0.27406027 
> 7  0.35033643 0.22525597 0.81657974 0.000762193 0.88383211 0.98120966 
> 0.29471244 0.32119662 0.10313222 
> 8  0.40616362 0.37962815 0.80085463 0.919385580 0.47183711 0.15078169 
> 0.93693666 0.24638847 0.12288727 
> 9  0.07939773 0.39030956 0.50235863 0.516507293 0.49247563 0.30633870 
> 0.45665595 0.25479969 0.34689089 
> 10 0.68677267 0.32089352 0.61330153 0.444584299 0.15588483 0.30584289 
> 0.78482250 0.55628942 0.81763581 
> 11 0.47406350 0.75586693 0.19546691 0.698137899 0.47609057 0.56439955 
> 0.33120842 0.54064656 0.36384570 
> 12 0.73796417 0.32741375 0.60800036 0.249716033 0.21919825 0.14749886 
> 0.53495852 0.74101013 0.69063797 
> 13 0.87890769 0.77631054 0.76307442 0.561350947 0.73865259 0.58031305 
> 0.06972116 0.53286669 0.09135791 
> 14 0.91022993 0.52290742 0.21219953 0.209784849 0.90892801 0.03580675 
> 0.19870342 0.79300520 0.85703181 
> 15 0.11331488 0.67744821 0.96226396 0.350925439 0.32038355 0.39465379 
> 0.38653925 0.09538576 0.04436648 
> 16 0.71950535 0.77548893 0.60316799 0.123102348 0.10200008 0.05392754 
> 0.17026972 0.17092818 0.35550621 
> 17 0.29593089 0.75526797 0.52088596 0.629731365 0.13592383 0.20219434 
> 0.63906356 0.55297375 0.30580842 
> 18 0.02915505 0.56244353 0.62397566 0.770202648 0.07929744 0.08574671 
> 0.36506494 0.47563923 0.84796898 
> 19 0.27369892 0.95739919 0.63443013 0.810165262 0.10230919 0.52165672 
> 0.84467928 0.60684813 0.02245486 
> 20 0.31494866 0.26169713 0.84314426 0.239598362 0.59996122 0.46954979 
> 0.99728261 0.28905422 0.91817317 
>          h 10 
> 1  0.552413907 
> 2  0.130387427 
> 3  0.523121318 
> 4  0.610000351 
> 5  0.005378552 
> 6  0.275925081 
> 7  0.939273614 
> 8  0.152024143 
> 9  0.216325412 
> 10 0.577869906 
> 11 0.484999656 
> 12 0.686217251 
> 13 0.920351777 
> 14 0.924500707 
> 15 0.577019180 
> 16 0.824386203 
> 17 0.130089829 
> 18 0.539668426 
> 19 0.776488706 
> 20 0.992742685 
> 
> 
> and i have a vector of strings which I called vars. 
> 
>> vars 
> [1] "h 8"  "h 4"   "h 10" "h 1" 
> 
> 
> the variables inside vars are subset of the column names of x.  The order is 
> important. In my dataframe, I want to obtain the following: 
> 
>>newdata 
>           h 8        h 4        h 10         h 1 
>  [1,] 0.65259411 0.093909834 0.552413907 0.38971928 
>  [2,] 0.84588084 0.871781822 0.130387427 0.51890830 
>  [3,] 0.68416629 0.239716639 0.523121318 0.94057256 
>  [4,] 0.82217244 0.378197899 0.610000351 0.19895720 
>  [5,] 0.66542828 0.732466508 0.005378552 0.27899679 
>  [6,] 0.65574673 0.866099979 0.275925081 0.69375077 
>  [7,] 0.32119662 0.000762193 0.939273614 0.35033643 
>  [8,] 0.24638847 0.919385580 0.152024143 0.40616362 
>  [9,] 0.25479969 0.516507293 0.216325412 0.07939773 
> [10,] 0.55628942 0.444584299 0.577869906 0.68677267 
> [11,] 0.54064656 0.698137899 0.484999656 0.47406350 
> [12,] 0.74101013 0.249716033 0.686217251 0.73796417 
> [13,] 0.53286669 0.561350947 0.920351777 0.87890769 
> [14,] 0.79300520 0.209784849 0.924500707 0.91022993 
> [15,] 0.09538576 0.350925439 0.577019180 0.11331488 
> [16,] 0.17092818 0.123102348 0.824386203 0.71950535 
> [17,] 0.55297375 0.629731365 0.130089829 0.29593089 
> [18,] 0.47563923 0.770202648 0.539668426 0.02915505 
> [19,] 0.60684813 0.810165262 0.776488706 0.27369892 
> [20,] 0.28905422 0.239598362 0.992742685 0.31494866 
> 
> I tried to do the following but it does not give me what I want: 
> 
> x[names(x)==names(x[names(x)%in%vars])] 
> 
> 
> Thank you very much. 
> 
> ~Christy 
> 
> 
> 
> 
> -- 
> View this message in context: http://r.789695.n4.nabble.com/how-to-create-a-new-data-given-a-vector-of-variable-names-tp4630024.html
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> 
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