Hi Alex,

Here is one way:

s <- "12/31/11 23:45"
strsplit(s, " ")[[1]]
# [1] "12/31/11" "23:45"
*

HTH,
Jorge.-

*

On Wed, May 2, 2012 at 4:00 PM, Alex Roth <> wrote:

> Hello there, I was wondering if you could help me with a quick R issue.
>
> I have a data set where one of the columns has both date and time in
> it, e.g. "12/31/11 23:45" in one cell. I want to use R to split this
> column into two new columns: date and time.
>
> One of the problems with splitting here is that when the dates go into
> single digits there are no 0's in front of months January-September
> (e.g., January is represented by 1 as opposed to 01), so every entry
> is a different length. Therefore, splitting by the space is the only
> option, I think.
>
> Here's the coding I've developed thus far:
>
> z$dt <- z$Date                    #time and date is all under z$Date
> foo <- strsplit(" ", z$dt)         #attempted split based on the space
>
> And then if that were to work, I would proceed use the coding:
>
> foo2 <- matrix(unlist(foo), ncol = 2, byrow=TRUE)
> z$Date <- foo[ ,1]
> z$Time <- foo[ ,2]
>
> However, foo <- strsplit(" ", z$dt) isn't working. Do you know what
> the problem is? If you could respond soon, that would be greatly
> appreciated!
>
> Thanks so much!
> Alex
>
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