Hello,

I can get the median for each factor, but I'd like another column to go
with each factor. The nm column is a long name for the lvls column. So
unique work except for the order can get messed up.

Example:
x =
data.frame(val=1:10,lvls=c('cat2',rep("cat1",4),rep("cat2",4),'cat1'),nm=c('longname2',rep("longname1",4),rep("longname2",4),'longname1'))
 x
val lvls        nm
1    1 cat2 longname2
2    2 cat1 longname1
3    3 cat1 longname1
4    4 cat1 longname1
5    5 cat1 longname1
6    6 cat2 longname2
7    7 cat2 longname2
8    8 cat2 longname2
9    9 cat2 longname2
10  10 cat1 longname1

unique doesn't work in data.frame:
 mdn = do.call(rbind,lapply(split(x[,1], x[,2]), median))
 data.frame(mdn,ln=as.character(unique(x[,3])))
mdn        ln
cat1   4 longname2
cat2   7 longname1

I want:
mdn        ln
cat1   4 longname1
cat2   7 longname2

Thank you very much!

PS - looking for simple'ish solutions. I know I can do it with loops and
merges, but is there an option I am not using here?

Ben

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