?formatC

HTH,
Jorge.-*
*

On Sun, Feb 12, 2012 at 10:56 PM, z2.0 <> wrote:

> Question:
>
> I'm trying to use paste() with rep() to reformat a series of values as zip
> codes. e.g., if column 1 looks like:
>
> 52775
> 83111
> 99240
> 4289
> 112
> 57701
> 20001
>
> I want rows 4 and 5 to read,
>
> "04289"
> "00112"
>
> My thought was this:
>
> > perry_frame$zip <- ifelse(nchar(as.character(perry_frame$zip))<5,
>
>
> paste(rep("0",times=(5-nchar(as.character(perry_frame$zip)))),perry_frame$zip,sep=''),
>  as.character(perry_frame$zip))
>
> But R throws the following:
>
> Error in rep("0", times = (5 - nchar(as.character(perry_frame$zip)))) :
>  invalid 'times' argument
>
> Is there a reason this doesn't work?
>
> Thanks,
>
> Zack
>
> --
> View this message in context:
> http://r.789695.n4.nabble.com/Assigning-a-function-to-the-times-argument-of-rep-tp4382849p4382849.html
> Sent from the R help mailing list archive at Nabble.com.
>
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