2012/1/10 syrvn <mentor_@gmx.net>

> And why does kruskal.test(x~y) differ from kruskal.test(f~d)??
>

Your formula is wrong, but function doesn't see errors.
"formula
a formula of the form lhs ~ rhs where lhs gives the data values and rhs the
corresponding groups."
And that leads to kruskal.test(d~as.factor(f)) which is fine.



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