Thank you for the help, I knew it could be done with a member of the apply family.  I struggle with apply stuff though, its not always intuitive for me with these functions.

Cheers,
 JR
________________________________
From: Sarah Goslee [via R] [mailto:ml-node+s789695n4144538h8@n4.nabble.com]
Sent: Thursday, December 01, 2011 6:44 PM
To: ROLL Josh F
Subject: Re: Summarizing elements of a list

How about:

lapply(Version1_, subset, subset=c(TRUE, FALSE))
or sapply() depending on what you want the result to look like.

Thanks for the reproducible example.

Sarah

On Thu, Dec 1, 2011 at 5:17 PM, LCOG1 <[hidden email]</user/SendEmail.jtp?type=node&node=4144538&i=0>> wrote:

> Hi everyone,
>   I looked around the list for a while but couldn't find a solution to my
> problem.  I am storing some results to a simulation in a list and for each
> element i have two separate vectors(is that what they are called, correct my
> vocab if necessary). See below
>
> Version1_<-list()
> for(i in 1:5){
>        Version1_[[i]]<-list(First=rnorm(1),Second=rnorm(1))
> }
>
> What I want is to put all of the elements' 'First' vectors into a single
> list to box plot. But whats a more elegant solution to the below?
>
> c(Version1_[[1]]$First,Version1_[[2]]$First,Version1_[[3]]$First,Version1_[[4]]$First,Version1_[[5]]$First)
>
> since i have 50 or more simulations this is impractical and sloppy.  Do I
> need to store my data differently or is their a solution on the back end?
> Thanks all.
>
> Josh
>
--
Sarah Goslee
http://www.functionaldiversity.org

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