Try xts (tsObj, order.by=index (tsobj))
On Nov 26, 2011 10:57 AM, "Kevin Burton" <rkevinburton@charter.net> wrote:

> I have two time series
>
>
>
> a <- ts(1:10, start=c(1,6), end=c(2,5), frequency=10)
>
> b <- ts(1:5, start=c(2,1), end=c(2,5), frequency=10)
>
>
>
> Obviously 'b' is a subset of 'a'. I want a single index value indicating
> where that start of 'b' lines up with the start of 'a'. So in this simple
> example I would expect an index of 5. I was playing with 'merge'. But, for
> a
> 'ts' object this does not produce anything that is useful:
>
>
>
> > merge(a,b)
>
>  x
>
> 1 1
>
> 2 2
>
> 3 3
>
> 4 4
>
> 5 5
>
>
>
> I get the same answer if I use 'merge(b,a)' so I don't know how to convert
> this result to something useful. So then I decided to use 'xts'. But the
> conversion fails:
>
>
>
> > ax <- as.xts(a)
>
> Error in as.xts.ts(a) : could not convert index to appropriate type
>
>
>
> For this simple example I could code it myself using a simple for loop but
> if I add capability to handle missing dates, different frequencies, etc. it
> gets complicated very fast.  It seems that 'xts' has more extensive date
> handling facilities that 'ts' but I am stuck since it doesn't look like I
> can convert from 'ts' to 'xts'.
>
>
>
> Thanks in advance for your suggestions.
>
>
>
> Kevin
>
>
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>
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