Dear Mr. Baddeley
 
I just graduated from a Masters in Applied Mathematics on Jun19th. My thesis was about spatial distribution /a nalysis of some trees in a part of  the Congo Basic Forest.
In my thesis I used your spatial package in R, and today I'm doing a more deeper study about how we choise the r distance in Function F(). I would like to
be able to understand about value of rmaxdefault as:
 
ripley <- min(diff(W$xrange), diff(W$yrange))/4
rlarge <- if (!missing(lambda)) sqrt(1000/(pi * lambda)) else Inf
rmax <- min(rlarge, ripley)

 For the ripley's calculation, I found your explanation in the internet but for the rlarge I couldn't find it. Could you explain why it is using the value inside of the sqrt (1000/(pi * lambda)).
 
Many thanks in advance if you do have the time to answer,
 
Myriam Saavedra  
Universidad San Francisco de Quito
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