Hi all,
Thanks for the suggestions.
What I ended up using was


x=aggregate(dat,by=list(dat$DOY,dat$Hour),mean)

where is my matrix and DOY is day of year. This gives me hourly means for
each day (apologies for not being more specific with my question). This
works for now but I'll probably want to do half hourly and then 15
s averaging later on, and I'm not sure how to do this, as those intervals
don't exist as columns.

Rollapply did not seem to reduce the total number of points, but just
smoothed out the vectors.

Any more suggestions? Thanks again guys.
On Mon, Jul 11, 2011 at 4:23 PM, David Winsemius <dwinsemius@comcast.net>wrote:

>
> On Jul 11, 2011, at 9:23 AM, Joshua Wiley wrote:
>
>  Hi,
>>
>> Take a look at package "zoo", perhaps something like:
>>
>> require(zoo)
>> x <- rnorm(10000) # hypothetical data
>> m <- rollapply(zoo(x), width = 100, FUN = mean, by = 100)
>>
>>  Definitely a better answer, but if all your rolling averages were of the
> form you suggested, then rollapply might be overkill, since tapply could
> easily do it:
>
> tapply(x, rep(1:100, each=100), mean)
>
> If you were always using non-overlapping blocks, then something like
>
> tapply(x, rep(1:( length(x)/wid ) , each= wid) , mean)
>
> Which will throw an error if length is not an integer multiple of "wid"
>
>
>  Another (bit more of a hack) option would be:
>>
>> ## convert vector to matrix byrows with 100 columns per row
>> ## (where 100 is the number of points you want at a time)
>> ## use rowMeans function to get mean of each row quickly
>> m2 <- rowMeans(matrix(x, ncol = 100, byrow = TRUE))
>>
>>
>> ?rollapply # from package zoo
>> ?rowMeans # in base
>>
>
>
> For Joshua's colMeans(matrix(..)) approach you need to be careful "at the
> end" because of recycling or at least heed warnings. I suspect that
> rollapply has protections built-in to avoid spurious recycling.
>
> > matrix(c(1,2,3), 2, byrow=TRUE)
>     [,1] [,2]
> [1,]    1    2
> [2,]    3    1
>
> --
> David.
>
>
>
>> HTH,
>>
>> Josh
>>
>> On Mon, Jul 11, 2011 at 2:23 AM, M. B <workstuffr@googlemail.com> wrote:
>>
>>> Hello,
>>> I am running R on Linux and have a column of data 10000 points long. I
>>> would
>>> like to take a moving average of say 100 points at a time, so I end up
>>> with
>>> one column of 100 points. What is the simplest way of doing this?  I
>>> would
>>> like to be able to adjust the width of the averaging blocks.
>>>
>>> Thanks much!
>>>
>>>       [[alternative HTML version deleted]]
>>>
>>
>>
>
> David Winsemius, MD
> West Hartford, CT
>
>

	[[alternative HTML version deleted]]

