All right then--I shall get bash away. Thanks a lot.

On Mon, May 9, 2011 at 2:55 PM, Deepayan Sarkar
<deepayan.sarkar@gmail.com>wrote:

> On Mon, May 9, 2011 at 8:23 PM, Dat Mai <dat.d.mai@gmail.com> wrote:
> > Thanks for the help! Though, when I do this, I get a message saying
> "Error
> > using packet 1 value where TRUE/FALSE." Would that have anything to do
> with
> > this set of code?
>
> It might. (As we don't know what you "did", we can't really say.)
>
> > On Sun, May 8, 2011 at 3:00 PM, Deepayan Sarkar <
> deepayan.sarkar@gmail.com>
> > wrote:
> >>
> >> On Fri, May 6, 2011 at 10:21 PM, Dat Mai <dat.d.mai@gmail.com> wrote:
> >> > Hello all,
> >> >
> >> > I'm trying  to create a heatmap using 2 matrices I have: z and v. Both
> >> > matrices represent different correlations for the same independent
> >> > variables. The problem I have is that I wish to have the values from
> >> > matrix
> >> > z to be represented by color intensity while having the values from
> >> > matrix v
> >> > to be represented by circle size. I currently have the following in
> >> > front of
> >> > me and an unsure of what to add or change in order to achieve that
> goal.
> >> >
> >> > panel.corrgram.2 =
> >> > function(x, y, z, subscripts, at = pretty(z), scale = 0.8, ...)
> >> > {
> >> >  require("grid", quietly = TRUE)
> >> >  x <- as.numeric(x)[subscripts]
> >> >  y <- as.numeric(y)[subscripts]
> >> >  z <- as.numeric(z)[subscripts]
> >> >  zcol <- level.colors(z, at = at, ...)
> >> >  for (i in seq(along = z))
> >> >  {
> >> >    lims <- range(0, z[i])
> >> >    tval <- 2 * base::pi * seq(from = lims[1], to = lims[2], by = 0.01)
> >> >    grid.polygon(x = x[i] + .5 * scale * c(0, sin(tval)),
> >> >      y = y[i] + .5 * scale * c(0, cos(tval)),
> >> >      default.units = "native",
> >> >      gp = gpar(fill = zcol[i]))
> >> >    grid.circle(x = x[i], y = y[i], r = .5 * scale,
> >> >      default.units = "native")
> >> >  }
> >> > }
> >>
> >> Probably this modification
> >>
> >> panel.corrgram.2 <-
> >>    function(x, y, z, v, subscripts, at = pretty(v), scale = 0.8, ...)
> >> {
> >>    require("grid", quietly = TRUE)
> >>    x <- as.numeric(x)[subscripts]
> >>    y <- as.numeric(y)[subscripts]
> >>    z <- as.numeric(z)[subscripts]
> >>    zcol <- level.colors(v, at = at, ...)
> >>
> >>    <Rest unchanged>
> >>
> >>
> >> followed by
> >>
> >> levelplot(signif(z,3), v = v, panel = panel.corrgram.2, ...)
> >>
> >> will do it.
> >>
> >> -Deepayan
> >>
> >>
> >> >
> >> > k=levelplot(signif(z,3), scales = list(x = list(rot = 45)),
> >> > col.regions=col.sch, panel = panel.corrgram.2,
> >> > label = num.circ, xlab="", ylab="", main=paste(output,"receptor
> >> > response"))
> >> > print(k)
> >> >
> >> > --
> >> > Best,
> >> > Dat Mai
> >> > PhD Rotation Student
> >> > Albert Einstein College of Medicine
> >> >
> >> >        [[alternative HTML version deleted]]
> >> >
> >> > ______________________________________________
> >> > R-help@r-project.org mailing list
> >> > https://stat.ethz.ch/mailman/listinfo/r-help
> >> > PLEASE do read the posting guide
> >> > http://www.R-project.org/posting-guide.html
> >> > and provide commented, minimal, self-contained, reproducible code.
>



-- 
Best,
Dat Mai
PhD Rotation Student
Albert Einstein College of Medicine

	[[alternative HTML version deleted]]

