Thanks Duncan for clarifying this.  I'm pretty a newbie to such type of
characters and special characters.  In R's gsub() what regular expressions
shall I use to handle all these situations?


On Fri, Apr 29, 2011 at 6:07 PM, Duncan Murdoch <murdoch.duncan@gmail.com>wrote:

> On 29/04/2011 7:41 PM, Miao wrote:
>
>> Hello,
>>
>> Can anyone help on gsub() in R?  I have a string like something below, and
>> wanted to delete all the strings with leading backslash, including
>> "\xa0On",
>> "\023, "\xab", and many others.   How should I write a regular expression
>> pattern in gsub()?  I don't care how many characters following backslash.
>>
>
>
> If those are R strings, none of them contain a backslash.  In R, a
> backslash would always be printed as \\.
>
> \x is the introduction to a hexadecimal encoding for a character; the next
> two characters show the hex digits.  So your first string contains a single
> character \xa0, the third one contains \xab, and so on.
>
> The \023 is an octal encoding for a single character.
>
> Duncan Murdoch
>
>
>
>> txt<- "Is This Thing\xa0On? http://bit.ly/jAbKem  wait \023 for people
>> \xab
>> and be patient :"
>>
>> Thanks in advance,
>> Miao
>>
>>        [[alternative HTML version deleted]]
>>
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>>
>
>


-- 
proceed everyday

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