Hi,

thank you for the response. What I actually want to do is pick automatically
the results of the various outputs (which I have already defined as
variables, e.g. output.1,output.2,etc) and insert them into a table. The
list variable would be redundant since in order to create the data frame I
would rather type data.frame(results=rbind(output.1,output.2,etc.)). If I
had 100 outputs, this would be much work. I rather meant something like
for(i in 1:100) {x=data.frame(results=rbind(output.[[i]]))}, which does not
work though. It says that object "output." cannot be found.

Kind Regards



On Thu, Apr 28, 2011 at 4:31 PM, jim holtman <jholtman@gmail.com> wrote:

> Yes you can, but there is not enough explaination as to what you
> really want to do.  I would suggest that you look at using a 'list'
> instead of individual objects:
>
> myList <- list(output.1 = rbind('a','b'), output.2 = rbind('c','d'), ...)
>
> Then you can use 'lapply' to operation on the elements.
>
> On Thu, Apr 28, 2011 at 10:16 AM, ivan <i.petzev@gmail.com> wrote:
> > Hi,
> >
> > is there a possibility to use global variables in a for loop. More
> > specifically, I want to do the following:
> >
> > output.1<-rbind("a","b")
> > output.2<-rbind("c","d")
> > output.3<-rbind("e","f")
> > .
> > .
> > .
> > output.n<-rbind(...,...)
> >
> > next I want to create a data frame with two columns:
> >
> > Outputs
> > Values  output.1 "a","b"  output.2 "c","d"  output.3 "e","f"  .
> >  .
> >  output.n …,…
> > My problem is that I do not how to define a loop over global variables.
> > Anybody an idea?
> >
> > Thanks.
> >
> >        [[alternative HTML version deleted]]
> >
> >
> > ______________________________________________
> > R-help@r-project.org mailing list
> > https://stat.ethz.ch/mailman/listinfo/r-help
> > PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> > and provide commented, minimal, self-contained, reproducible code.
> >
> >
>
>
>
> --
> Jim Holtman
> Data Munger Guru
>
> What is the problem that you are trying to solve?
>

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