The optimal way of doing it depends on how you want to use the result. An
easy way has been recommended - if you have

boo <- list(first=data.frame(a=1:5, b=2:6), second=data.frame(a=6:10,
b=7:11))

.. then

sink("boo.txt")
boo   # or: print(boo)
sink()

... will put it all in the same file, the same way it would ordinarily
appear on the screen . But this is not a csv file (Comma Separated Values),
and it's not easily usable by other software (try re-reading it to R). I
think a better way for most purposes would be to make it a big table and add
an extra variable (say, GROUP). To do it in one go you might use something
like

boo <- mapply(function(x,y) within(x, GROUP <- y), boo, names(boo),
SIMPLIFY=FALSE)

... then put the different pieces together using something like

do.call(rbind, boo)

# resulting in something like this:
          a  b  GROUP
first.1   1  2  first
first.2   2  3  first
first.3   3  4  first
first.4   4  5  first
first.5   5  6  first
second.1  6  7 second
second.2  7  8 second
second.3  8  9 second
second.4  9 10 second
second.5 10 11 second

... and the result is what you can write to a csv file and later easily
re-read using any software

write.csv(do.call(rbind, boo), "boo.csv")

Regards,
Kenn

On Wed, Mar 16, 2011 at 3:14 PM, andrija djurovic <djandrija@gmail.com>wrote:

> Soryy, I didn't explain well what I want. I would like to have a table in
> csv on txt file like this:
>
> $A
>      q1    q2
> aa     1     3
> bb     2 check
> cc check     5
> $B
>      q1 q2
> aa check  4
> bb     1  5
> The same as write.csv of any data frame.
>
>
>
>
> On Wed, Mar 16, 2011 at 4:03 PM, Henrique Dallazuanna <wwwhsd@gmail.com
> >wrote:
>
> > Use dput:
> >
> > dput(l, file = "l_str.txt")
> >
> > Then, to read again:
> >
> > l <- dget(file = 'l_str.txt')
> >
> > On Wed, Mar 16, 2011 at 11:55 AM, andrija djurovic <djandrija@gmail.com>
> > wrote:
> > > Hi everybody.
> > >
> > > I have list like this:
> > >
> > > l<-list(data.frame(q1=c(1,2,"check"),q2=c(3,"check",5)),
> > > data.frame(q1=c("check",1),q2=c(4,5)))
> > > names(l)<-c("A","B")
> > > rownames(l[[1]])<-c("aa","bb","cc")
> > > rownames(l[[2]])<-c("aa","bb")
> > >
> > > Every object has the same number of columns but different number of
> rows.
> > > Does anyone know if it is possible to export such kind of list, into
> one
> > csv
> > > file, and  keeping all the names?
> > >
> > > Thanks in advance
> > >
> > > Andrija
> > >
> > >        [[alternative HTML version deleted]]
> > >
> > > ______________________________________________
> > > R-help@r-project.org mailing list
> > > https://stat.ethz.ch/mailman/listinfo/r-help
> > > PLEASE do read the posting guide
> > http://www.R-project.org/posting-guide.html<
> http://www.r-project.org/posting-guide.html>
> > > and provide commented, minimal, self-contained, reproducible code.
> > >
> >
> >
> >
> > --
> > Henrique Dallazuanna
> > Curitiba-Paraná-Brasil
> > 25° 25' 40" S 49° 16' 22" O
> >
>
>         [[alternative HTML version deleted]]
>
>
> ______________________________________________
> R-help@r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
>

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