That's a smart way to do this. Thanks!

John




________________________________
From: Berend Hasselman <bhh@xs4all.nl>
To: r-help@r-project.org
Sent: Mon, March 14, 2011 10:49:37 AM
Subject: Re: [R] ideas on sorting


array chip wrote:
> 
> Hi, I have a character vector as below:
> 
> a<-c('10','3R','4','4R','5','5R','6','6R','7','8','9','7R','1','10R','11'
> ,'11R','12','12R','13','13R','14','14R','15','15R','1R','2','2R','3','8R'
> ,'9R')
> 
> Is there a clever way to sort this easily to return a vector of index that
> would 
> produce a vector as below:
> 
> a[index]:
> 
>  [1] "1"   "2"   "3"   "4"   "5"   "6"   "7"   "8"   "9"   "10" 
> [11] "11"  "12"  "13"  "14"  "15"  "1R"  "2R"  "3R"  "4R"  "5R" 
> [21] "6R"  "7R"  "8R"  "9R"  "10R" "11R" "12R" "13R" "14R" "15R"
> 

Try

index <- order(as.numeric(sub('R','000',a)))

/Berend


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