You can use the summary with the split argument.

See
?summary.aov
for an example.

This gives similar results to the regression coefficients approach that Ista
Zahn
suggested.  I usually prefer the ANOVA table approach for factors.

On Thu, Feb 3, 2011 at 3:36 AM, Asan Ramzan <asanramzan@yahoo.com> wrote:

> Hello R-help
> I don’t know how to interpret significance from the contr.poly() function .

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