Dear Sir,

Sorry to bother you again. Sir, the R code provided by you gives me following output.

> yy <- lapply(c(257, 520, 110), seq, to=0, by=-100)
> yy
[[1]]
[1] 257 157  57

[[2]]
[1] 520 420 320 220 120  20

[[3]]
[1] 110  10

The biggest constraint for me is here as an example I have taken only three cases i.e. c(257, 520, 110), however in reality I will be dealing with no of cases and that number is unknown. But your code will certainly generate me the required numbers. In above case for doing further calculations, I can define say 

yy1 = as.numeric(yy[[1]])
yy2 = as.numeric(yy[2]])
yy3 = as.numeric(yy[[3]])

But when the number of cases are unknown, perhaps this is not the practical way of me defining individually. So is there any way that I can have all the sequence numbers generated can be accommodated in a single dataframe. I sincerely apologize for disturbing you Sir and hope I am able to put up my problem in a proper manner.

Regards

Vincy Pyne


--- On Thu, 12/9/10, Jan van der Laan <rhelp@eoos.dds.nl> wrote:

From: Jan van der Laan <rhelp@eoos.dds.nl>
Subject: Re: [R] Sequence generation in a table
To: r-help@r-project.org, vincy_pyne@yahoo.ca
Received: Thursday, December 9, 2010, 10:57 AM

Vincy,

I suppose the following does what you want. yy is now a list which allows for differing lengths of the vectors.

> yy <- lapply(c(257, 520, 110), seq, to=0, by=-100)
> yy[[1]]
[1] 257 157  57
> yy[[2]]
[1] 520 420 320 220 120  20


Regards,
Jan


On 9-12-2010 11:40, Vincy Pyne wrote:
> c(257, 520, 110)



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