Hi Sudhakar,

Use

 diff(msales)[which.max(diff(msales))]

HTH,
Jorge


On Sat, Oct 30, 2010 at 12:38 PM, Sudhakar Kumar <> wrote:

>
> Thanks Jorge. That is very helpful. Hadnt seen 'which' yet.
>
> So it is a matter of combining functions if I wanted both the value and the
> month?
>
> From:
> Date: Sat, 30 Oct 2010 12:33:12 -0400
> Subject: Re: [R] Using names function
> To: ksudhakar@live.com
> CC: r-help@r-project.org
>
> Hi Sudhakar,
> Take a look at ?which.max
>
>
> msales <- c(2700, 2600, 3050) names(msales) <- c("Jan", "Feb", "Mar")
>
> names(which.max(diff(msales)))# [1] "Mar"
>
> HTH,Jorge
>
> On Sat, Oct 30, 2010 at 12:27 PM, Sudhakar Kumar <> wrote:
>
>
>
>
> Just starting on my journey to learn R and the book I am using is "Using R
> for Introductory Statistics"
>
>
>
> One of the problems (page 15, 1.10) goes as follows:
>
> The monthly sales fig for 2002 were (2700, 2600, 3050, . . ). Using diff()
> find the month with greatest increase from prev month.
>
>
>
> I created a msales var:
>
> msales = c(2700, 2600, 3050 . . )
>
>
>
> I named them:
>
> names(msales)=c("Jan", Feb", "Mar" . . .)
>
>
>
> to find the month with greatest increase from prev month:
>
> max(diff(msales))
>
>
>
> I get the numeric value displayed when I execute the above function, but
> not the month. cumsum(msales) displays the results under each month, but not
> max. How can I get both the month and value displayed?
>
>
>
> Thanks
>
> -Sudhakar
>
>
>
> ps: no, I am not a student seeking answers to exercises :)
>
>
>
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>
>
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>
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>
>
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