Hi Gregory,

May be this?

# some data
set.seed(123)
x <- factor(sample(0:1, 20, TRUE))
x
# [1] 0 1 0 1 1 0 1 1 1 0 1 0 1 1 0 1 0 0 0 1
# Levels: 0 1

as.numeric(as.factor(x))
# [1] 1 2 1 2 2 1 2 2 2 1 2 1 2 2 1 2 1 1 1 2

as.numeric(as.character(x))
 [1] 0 1 0 1 1 0 1 1 1 0 1 0 1 1 0 1 0 0 0 1

HTH,
Jorge



On Mon, Sep 20, 2010 at 10:40 PM, Gregory Ryslik <> wrote:

> Hm,
>
> Now that you mention it, I believe they are factors. They just appeared as
> 0 or 1 so I treated them as numbers.
>
> Once I found out they were factors I tried using the as.numeric() but that
> makes it 1 or 2 as before. How do I actually make it keep the factor number?
>
> Thanks,
> Greg
> On Sep 20, 2010, at 10:28 PM, David Winsemius wrote:
>
> >
> > On Sep 20, 2010, at 10:12 PM, Gregory Ryslik wrote:
> >
> >> Hi,
> >>
> >> I have a list of 5 main elements where each main element has 247 atomic
> entries either 0 or 1. I need to get this into a 247x5 matrix so I do
> "do.call(cbind, mylist)".  However, it renumbers 0 to a 1 and the 1 to a 2
> so that my matrix is filled with 1's and 2's.
> >>
> >
> > If I had such a problem I would see if this were more effective:
> >
> > matrix(unlist(mylist), length(mylist[[1]]) )
> >
> > (There is the column major order default of R matrices.)
> >
> >> I understand I can fix it in this case by doing a replace but I would
> like to avoid that step. Further, sometimes, my list entries will be from 0
> to n. I don't want to have to always renumber all the possibilities.
> >>
> >> I'm not quite sure why this is going on because when I build the
> following: l <- list(c(1,2,3),c(1,2,3),c(1,2,3))
> >> and execute do.call(cbind, l) it works just fine and there is no
> renumbering!
> >
> > I wouldn't have expected it either, but you only provided an example of
> what did work. My attempt at reproducing your problem also failed:
> >
> > > ll <- list(a=c(1,0,1,1,0), b=c(0,1,0,0,1)  )
> > > do.call(cbind, ll)
> >     a b
> > [1,] 1 0
> > [2,] 0 1
> > [3,] 1 0
> > [4,] 1 0
> > [5,] 0 1
> >
> > I am wondering if you are dealing with factors and have not looked at
> your "list" with str(). Haven't tried my method above to see what would
> happen in tat instance.
> >
> >
> >
> >>
> >> Thanks,
> >> Greg
> >>      [[alternative HTML version deleted]]
> >>
> >> ______________________________________________
> >> R-help@r-project.org mailing list
> >> https://stat.ethz.ch/mailman/listinfo/r-help
> >> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> >> and provide commented, minimal, self-contained, reproducible code.
> >
> > David Winsemius, MD
> > West Hartford, CT
> >
>
> ______________________________________________
> R-help@r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>

	[[alternative HTML version deleted]]

