Try this:

aggregate(rep(1, nrow(x)), x, sum)

On Fri, Sep 17, 2010 at 9:19 AM, Alaios <alaios@yahoo.com> wrote:

> Hello everyone,
> please consider the following lines of a matrix
>
>
> [574,]   59   32
> [575,]   59   32
> [576,]   59   32
> [577,]   59   32
> [578,]   59   32
> [579,]   59   32
> [580,]   59   32
> [581,]   60   32
> [582,]   60   33
> [583,]   60   33
> [584,]   60   33
> [585,]   60   33
> [586,]   60   33
> [587,]   60   33
> [588,]   60   33
> [589,]   60   33
> [590,]   60   33
> [591,]   61   33
> [592,]   61   33
> [593,]   61   33
> [594,]   61   33
> [595,]   61   33
> [596,]   61   33
> [597,]   61   33
> [598,]   61   33
> [599,]   61   33
> [600,]   61   33
> [601,]   62   34
>
> Is it possible somehow to count the similarities between the first and
> second
> column and put them on a third column like this?
>
> 59 32 3
> 60 33 5
> 62 34 1
>
> where (3,5,1 are the frequencies for (59,32), (60,33) and (62,34)
>
> Best Regards
> Alex
>
>
>
>
>        [[alternative HTML version deleted]]
>
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> and provide commented, minimal, self-contained, reproducible code.
>



-- 
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40" S 49° 16' 22" O

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