  Hi,

I thought you were looking for table(), but the other answers gave you 
something really different; I might have wrongly understood your question.

HTH,
Ivan

Le 8/20/2010 12:32, Alain Guillet a écrit :
>  Hi,
>
> You can try sapply(levels(as.factor(dat1)),nchar)
>
> Alain
>
> On 20-Aug-10 12:01, Ron Michael wrote:
>> Dear all, let suppose I have following vector:
>>
>>> dat1<- c(rep("asd", 5), rep("xyz", 12), rep("erd", 17))
>>> dat1<- dat1[sample(1:length(dat1), length(dat1), replace=F)]
>>> dat1
>>   [1] "erd" "xyz" "erd" "asd" "asd" "erd" "xyz" "asd" "erd" "erd" 
>> "asd" "xyz" "erd" "asd" "xyz" "xyz" "erd" "xyz" "erd"
>> [20] "erd" "erd" "xyz" "xyz" "erd" "erd" "erd" "erd" "xyz" "xyz" 
>> "xyz" "erd" "xyz" "erd" "erd"
>>
>>   Here I want to know the length of replications for each unique 
>> items viz "asd", "xyz", and "erd". Is there any R function available 
>> to directly implement that?
>>   Thanks,
>>
>>
>>     [[alternative HTML version deleted]]
>>
>>
>>
>> ______________________________________________
>> R-help@r-project.org mailing list
>> https://stat.ethz.ch/mailman/listinfo/r-help
>> PLEASE do read the posting guide 
>> http://www.R-project.org/posting-guide.html
>> and provide commented, minimal, self-contained, reproducible code.
>

-- 
Ivan CALANDRA
PhD Student
University of Hamburg
Biozentrum Grindel und Zoologisches Museum
Abt. Säugetiere
Martin-Luther-King-Platz 3
D-20146 Hamburg, GERMANY
+49(0)40 42838 6231
ivan.calandra@uni-hamburg.de

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