Thanks a lot, Dimitris!
I see - data should be defined precisely  as data.frame.


On Mon, Aug 16, 2010 at 2:47 PM, Dimitris Rizopoulos <
d.rizopoulos@erasmusmc.nl> wrote:

> better try it this way:
>
> DF <- data.frame(y = rnorm(100), x = rchisq(100, df = 3))
> m <- lm(y ~ x, DF)
> predict(m, data.frame(x = seq(-13, 13, 0.5)))
>
>
> I hope it helps.
>
> Best,
> Dimitris
>
>
>
> On 8/16/2010 2:37 PM, Trafim Vanishek wrote:
>
>>  Dear all,
>>
>> I have an error in the simple prediction function for lm().
>> Maybe someone experienced the same?
>>
>> xma<- matrix(data = 0, nrow = 100, ncol = 2)
>> xma[, 1]<- rnorm(100)
>> xma[, 2]<- rchisq(100, df = 3)
>>
>> m1<- lm(xma[, 1] ~ xma[, 2])
>> predict(m1, as.data.frame(seq(-13, 13, 0.5)))
>>
>>
>> Thanks a lot,
>> Trafim
>>
>>        [[alternative HTML version deleted]]
>>
>>
>> ______________________________________________
>> R-help@r-project.org mailing list
>> https://stat.ethz.ch/mailman/listinfo/r-help
>> PLEASE do read the posting guide
>> http://www.R-project.org/posting-guide.html<http://www.r-project.org/posting-guide.html>
>> and provide commented, minimal, self-contained, reproducible code.
>>
>>
> --
> Dimitris Rizopoulos
> Assistant Professor
> Department of Biostatistics
> Erasmus University Medical Center
>
> Address: PO Box 2040, 3000 CA Rotterdam, the Netherlands
> Tel: +31/(0)10/7043478
> Fax: +31/(0)10/7043014
>

	[[alternative HTML version deleted]]

