Hey,
Thanks a lot everyone.
Taking care of the NA's and setting right the type-casting I could apply
lapply.
I have read the documentation for R and it is mentioned that statistical and
mathematical methods could be applied across data frames but when lapply
didn't work (due to the above said errors) I assumed not all functions could
be applied. I was also skeptical as to the kind of output that would be
given by R as I only wanted the values of the coefficients.

Thanks a lot for clearing it up for me.

Regards,
Phani

On Tue, Jun 22, 2010 at 9:08 PM, Bert Gunter <gunter.berton@gene.com> wrote:

>
>
> Bert Gunter
> Genentech Nonclinical Biostatistics
>
>  -----Original Message-----
> From: r-help-bounces@r-project.org [mailto:r-help-bounces@r-project.org]
> On
> Behalf Of phani kishan
> Sent: Tuesday, June 22, 2010 8:10 AM
> To: David Winsemius
> Cc: r-help@r-project.org
> Subject: Re: [R] Applying forecast functions to columns in a data frame
>
> Simple operations like mean etc. can be applied
> using lapply but not statistical functions.
>
> --NONSENSE!
>
> func <- function(x){
>        ##write any function you like
>        z <- sin(x^2-2)+rnorm(length(x))
>        lm(z~ seq(along=z))
>        }
> dat <- data.frame(a=1:5,b=rnorm(5))
> lapply(dat,func)## could also have been inserted inline
>
>
> Have you read "An Introduction to R" where these sorts of things are
> discussed?
>
>
>
>
> Bert Gunter
> Genentech Nonclinical Biostatistics
>
>


-- 
A. Phani Kishan
3rd Year B.Tech
Dept. of Computer Science & Engineering
IIT MADRAS
Ph: +919962363545

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