Hi GL,

Tr this:

# example 1

list1 <- list(letters[1:7])

list1

list2 <- list(c('z','y','x','w','v','u','b'))

list2

mapply(function(x, y) any(x %in% y), list1, list2)



 # example 2

list2 <- list(c('z','y','x','w','v','u','t'))

list2

mapply(function(x, y) any(x %in% y), list1, list2)

HTH,
Jorge


On Sun, Jun 13, 2010 at 2:17 PM, GL <> wrote:

>
> Silly question, but, can I test to see if any value of list a is contained
> in
> list b without doing a loop? A loop is easy enough, but wanted to see if
> there was a cleaner way. By way of example:
>
> List 1: a, b, c, d, e, f, g
>
> List 2: z, y, x, w, v, u, b
>
> Return true, since both lists contain b
>
> List 1: a, b, c, d, e, f, g
>
> List 2: z, y, x, w, v, u, t
>
> Return false, since the lists have no mutual values
>
>
>
> --
> View this message in context:
> http://r.789695.n4.nabble.com/Are-any-values-in-one-list-contained-within-a-second-list-tp2253637p2253637.html
> Sent from the R help mailing list archive at Nabble.com.
>
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>

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