Hi Alex,

Here is a suggestion:

apply(combn(idx, 2), 2, paste, collapse = ".")

See ?combn, ?apply and ?paste for more information.

HTH,
Jorge


On Thu, Jun 3, 2010 at 3:08 PM, Alex van der Spek <> wrote:

> I can get the interactions between factors like this:
>
> > idx=c(1,3,6,9)
> > jdx=idx
> > levels(interaction(idx,jdx,lex.order=TRUE))
>  [1] "1.1" "1.3" "1.6" "1.9" "3.1" "3.3" "3.6" "3.9" "6.1" "6.3" "6.6"
> "6.9"
> [13] "9.1" "9.3" "9.6" "9.9"
>
> This list contains all possible interactions. Whereas I need only the
> combinations, e.g 4 over 2 = 6 total being
>
> "1.3 " "1.6" "1.9" "3.6" "3.9" "6.9"
>
> I have been unable to find how to get the combinations. Of course with some
> string manipulations this can be done for this toy example. There should be
> something in R to make this easy?
>
> Thanks in advance
> Alex van der Spek
>
> ______________________________________________
> R-help@r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>

	[[alternative HTML version deleted]]

