Could you provide us with dput(becva$V1[1])?
Cheers
Joris

On Wed, Jun 2, 2010 at 2:07 PM, Petr PIKAL <petr.pikal@precheza.cz> wrote:

> Dear all
>
> I encountered strange problem with regexpr replacement
>
> I made this character object
>
> str <- "02.06.10 12:40     "
>
> > str(str)
>  chr "02.06.10 12:40      "
>
> I read in an object which seems to be quite similar
>
> > str(as.character(becva$V1)[1])
>  chr "02.06.10 12:40   "
>
> However I can not remove trailing spaces from it
>
> > sub(' +$', '', as.character(becva$V1[1]))
>
> [1] "02.06.10 12:40   "
> > sub(' +$', '', str)
> [1] "02.06.10 12:40"
> >
>
> Do somebody have an idea what to do?
>
> $version.string
> [1] "R version 2.12.0 Under development (unstable) (2010-04-25 r51820)"
>
> on Windows
>
> Regards
> Petr
>
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> and provide commented, minimal, self-contained, reproducible code.
>



-- 
Joris Meys
Statistical Consultant

Ghent University
Faculty of Bioscience Engineering
Department of Applied mathematics, biometrics and process control

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