Try this:

dir()[file.info(dir())$isdir]


On Tue, Jun 1, 2010 at 11:06 PM, Nevil Amos <nevil.amos@gmail.com> wrote:

> How do I get a list of subdirectories only, not files, in a directory
>
>
> dir.create("test")
> setwd("test")
> dir.create("adir")
> dir.create("bdir")
> file.create("afile")
> dir()
>
> returns [1] "adir"  "afile" "bdir"
>
> in need to return [1] "adir"  "bdir"
>
> cheers
>
> Nevil Amos
>
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> and provide commented, minimal, self-contained, reproducible code.
>



-- 
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40" S 49° 16' 22" O

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