Hi Anna,

Here is a suggestion:

# creating L1
L1 <- lapply(1:5, function(x) matrix(rnorm(10), ncol = 2))
L1

# creating L2
L2 <- lapply(1:5, function(x) sample(5, 2))
L2

# defining a function
foo <- function(x, y) list(x[-y,])

# result
mapply(foo, L1, L2)

HTH,
Jorge

On Fri, Mar 26, 2010 at 5:34 PM, anna <> wrote:

>
> Hello guys,
> I have a list L1 of matrix. I have another list L2 with the same number of
> elements representing the row of the L matrix that I want to delete
> (L1[[i]][-L2[[i]],]) but I can't do this with lapply as it iterates through
> L1 (first argument) and not L2. Any idea?
>
> -----
> Anna Lippel
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