Dear Sir,
 
Thanks a lot for your quick solution. But still I will like someone to guide me the solution as per my requirement. The problem is actually I am not looking for the square of each term. I have used it to give some example since I didn't want to confuse the matter. My process is altogether different and I need to use loop. So here is my actual code. I am trying to use Historical simulation and for that I need to calculate LN(New rate / old rate for each of the instrument separately).
 
Here is my actual code -
 
ONS = read.csv('Instrument.csv')
n = length(ONS)
Y = NULL
B = array()
 
for (i in 1 : n)
 {
 Y[i] = ONS[i]
  j     <- 1
 for (j in 1:(length(Y[[i]])-1))
       {
  B[j]     <- log((Y[[i]][j+1])/(Y[[i]][j]))
 
                             
 j <- j+1
 

 }
 
 }

 


--- On Mon, 15/2/10, Benilton Carvalho <beniltoncarvalho@gmail.com> wrote:


From: Benilton Carvalho <beniltoncarvalho@gmail.com>
Subject: Re: [R] CORRECTION - Storing results in a loop
To: "Madhavi Bhave" <madhavi_bhave@yahoo.com>
Cc: r-help@r-project.org
Date: Monday, 15 February, 2010, 4:29 AM


sorry, meant to type:

B = ONS^2

cheers,
benilton

On Mon, Feb 15, 2010 at 12:28 PM, Benilton Carvalho
<beniltoncarvalho@gmail.com> wrote:
> maybe you just want
>
> Y = ONS^2
>
> ?
>
> b
>
> On Mon, Feb 15, 2010 at 12:22 PM, Madhavi Bhave <madhavi_bhave@yahoo.com> wrote:
>> Dear R Helpers
>>
>> (There is a small correction in my earlier mail. In the 'instrument.csv' file, I had mentioned only three columns. Actually there are 7 columns. I regret the error. Rest contents remains the same. Thanks)
>>
>> I have an 'instrument.csv' file with 7 instrument names and 5 rates each i.e. it has 7 columns and 6 rows (including row names).
>>
>> 'instrument.csv'
>>
>> instrument1      instrument2   ........     instrument7
>> 12                         5                              14
>> 11                         7                                7
>> 14                       11                                3
>>   8                       21                              10
>> 11                         3                                5
>>
>>
>> Following is my R code.
>>
>> ONS = read.csv('Instrument.csv')
>> n = length(ONS)
>>
>> Y = NULL
>> B = NULL
>>
>> for (i in 1 : n)
>>
>>  {
>>
>>  Y[i] = ONS[i]
>>
>>   for (j in 1 : length(Y[[i]]))
>>    {
>>    B[j] = (Y[[i]][j])^2
>>    }
>>
>>  }
>>
>> Problem is when I type B, I get the processed result only for the last column i.e. Y[7]. It doesn't store results for Y[1] to Y[7].
>>
>> I need B[1], B[2].......upto B[7].
>>
>> Please guide me how do I store individual column processed results?
>>
>> Thanking you all in advance
>>
>> Regards
>>
>> Madhavi
>>
>>
>>
>>
>>      The INTERNET now has a personality. YOURS! See your Yahoo! Homepage.
>>        [[alternative HTML version deleted]]
>>
>>
>> ______________________________________________
>> R-help@r-project.org mailing list
>> https://stat.ethz.ch/mailman/listinfo/r-help
>> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
>> and provide commented, minimal, self-contained, reproducible code.
>>
>>
>



      Your Mail works best with the New Yahoo Optimized IE8. Get it NOW! http://downloads.yahoo.com/in/internetexplorer/
	[[alternative HTML version deleted]]

